kvarnerexpress
Apr 25 2005, 09:18 PM
| | I have a form, from where the data is being posted to a php script. Now in the php script the script has to forward the data to another script with posted data. I know this can be done using header but i don't know how to keep the data posted with form in POST method.
For example:
The form below:
Code:
<form method="POST" action="1.php">
<input type="hidden" value="abc" name="t1">
<input type="submit">
</form>
Now its posting data using POST method to 1.php...and now 1.php will redirect everything to another php script with the data and it should be in POST method ...
How can i do this ?
Thanks.
|
Reply
snlildude87
Apr 25 2005, 09:29 PM
Hmm, you can have a hidden form with hidden inputs in 1.php... 1.php: CODE <?php
echo "<form method=\"POST\" action=\"[url of script to send info]\">\n\t";
echo "<input type=\"hidden\" name=\"[name of your choice]\" value=\"[value of the data from previous script]\">\n";
echo "<form>\n";
?> I hope this made sense, but this is essentially what you did in your example... I'm still a newbie to PHP, so I'm trying the best I can to help you. 
Reply
beeseven
Apr 25 2005, 09:45 PM
I'm not sure I completely understand, but I think you could do this: 1. Get the data from the form ($a = $_POST['a']; $b = $_POST['b'];) 2. Redirect with the data in the url (header("Location: http://aaa.aaaaa.aaa/ab.php?a=a&b=b"); die;) 3. Use $_GET to get the data ($a = $_GET['a']; $b =$_GET['b'];)
Reply
FaLgoR
Apr 26 2005, 05:07 PM
You can do it by two ways: 1°, using hidden inputs. 2°, add the values on the url, look: CODE
<? header("Location: page.php?t1=$t1&t2=$t2&t3=$t3"); ?>
Got it? =D
Reply
Newton
Apr 29 2005, 11:30 AM
If you need the data a few page access' later then just dump it in a cookie as a concatenated string.
Reply
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