I have been wrestling with this issue some time now and can't figure it out.
I have a dropdownmenu with some data (pulled from a database using php, but that's unimportant).
Now when one selects a item form that menu I want the page to which that item links to be opened in a layer.

There are 2 things Going on:

1. I use javascripts include('layer','content.php'); function to load a page in a layer.
Works like a charme.

2. the dropdown menu CAN open the page to which the items link in the same page using:

<SELECT NAME="SelectURL" onChange="document.location.href=
document.nav.SelectURL.options[document.nav.SelectURL.selectedIndex].value">

Works great too.


WHAT I DID TO COMBINE THIS:

<SELECT NAME="albums" id="albums" class="table" onChange="
include('thumbnaillayer', 'document.nav.SelectURL.options[document.nav.SelectURL.selectedIndex].value ');
">

seemed logical to me.

only what happens in real is this error:

Not Found
The requested URL /ghbstoernooi/document.nav.SelectURL.options[document.nav.SelectURL.selectedIndex].value was not found on this server.


--------------------------------------------------------------------------------

Apache/1.3.29 Server at localhost Port 80

What is going on here?
I can't be too far away form the solution since steps 1 and 2 work great. But I need a little push in the right direction....

Please, any help would be awesome! Thanks a lot in advance!

 

 

 

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What you are trying to do is run a server side code in the client. "include" is server side (php) code. Whatever is executed on "onchange" of dropdown *has* to be client side code since your browser doesn't know about server code. That doesn't work. if you want to include something, you can redirect browser to a pageinclude.php script with a parameter (depending on the selection of dropdown) and in your php, depending on parameter, you can include respective file.

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