Dark_Prisoner
Feb 26 2008, 07:15 PM
QUOTE(nooc @ Nov 19 2004, 11:02 PM)  CODE #include <stdio.h>
void fun(void)
{
#define fun() i=10
}
int main()
{
int i = 20;
fun();
printf("i = %d\n", i);
return 0;
} I think that this won't work : (i guess) we can't put preprocessor directives on a function If we can , it won't work also , because the compiler or the processor had completed the line : CODE fun(); so he won't replace it . if the preprocessor works in functions i guess this will be the answer CODE void fun(void)
{
#define printf("i = %d\n", i) i=0
}
int main()
{
int i = 20;
fun();
printf("i = %d\n", i);
return 0;
} What do you think ???
Reply
tricky77puzzle
Feb 27 2008, 12:41 AM
printf is a standard function in C. You can't modify it. Try doing the same thing in c++.
Reply
iGuest
Apr 30 2008, 01:52 PM
code for this program
C Code, Can U Solve This?
Easy code in 'C' program to prove pallidrome rule Thanking you, Vikram -question by vikram
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