Jul 25, 2008

Bin To Hex Converting?
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Bin To Hex Converting?

Chez
Feb 9 2006, 05:51 PM
I'm trying to convert a 32-bit Hex string into 32-bit binary and then back.
Whats the theory behind this? I was checking online and some articles said check each char divided against a power of 10. ... ? A bit confused here. Any help appreciated.

using SPIM
on Fedora Core platform

Reply

Cerebral Stasis
Feb 9 2006, 06:25 PM
I'm assuming that by "Hx" you mean hexadecimal. You may want to try one of the free conversion scripts found here.

Reply

Chez
Feb 9 2006, 06:46 PM
Yes, hexadecimal. But I was actually looking for code help, not an actual converter. thanks though.

I can convert from decimal to binary simply using a recurring function with remainders...

recurring function:
47 / 2 gives DIV=23 MOD=1, bin string = 1
23 / 2 gives DIV=11 MOD=1, bin string = 11
11/2 gives DIV=5 MOD=1, bin string = 111
5/2 gives DIV=2 MOD=1, bin string = 1111
2/2 gives DIV=1 MOD=0, bin string = 01111
1/2 gives DIV=0 MOD=1, bin string = 101111

but Hex is harder to code because it has letters as well as numbers. So I'm not sure how I can create a function that will do that.

not looking for code, just how would you go about converting hex to binary and then back again?

Reply

Chez
Feb 17 2006, 08:09 PM
ok, so I figured it out myself after days of reading up on the complexities of MIPS architecture. I basically IO-ed the HEX input into a register and used 'lb' to grab each character (by cooredinating ascii value). this is the part I had problems with previously: I didn't know the loaded byte would be converted to binary in the register, so I was origionally comparing ascii values. But lo and behold, Assembly language did not completely let me down once I figured you could compare chars as in C or Java simply by bordering your target char with single quotes. Once I figured that out, the whole comparison was a peice of cake. Finding, say, '3' would run through the converter loop and input 0011 to a string in another register, srl 4, increase position, and continue. Fairly easy once I got the jist of it. code follows:

QUOTE

# This program inputs a Hex number and
# converts it to Binary. Then alters the
# Binary number and outputs new Hex number.

.data
PROMPT: .asciiz "Enter Hex: "
ORI: .asciiz " "
RES: .asciiz " "
OUT: .asciiz " -> "
.text
main:
##################################
# INITIALIZE REGISTERS #
##################################
li $s0, 0 #INPUT HEX
li $s1, 0 #TEMP BYTE STORAGE
li $s2, 0 #I
li $s3, 0 #BINARY NUMBER
li $s4, 0 #TEMP BINARY NUMBER
li $s5, 0 #TEMP BINARY CHAR
la $s6, ORI #ORIGIONAL HEX
la $s7, RES #FINAL HEX

##################################
# MAIN #
##################################
j INPUT #PROMT FOR HEX AND STORE IT
START: j HIN #HEX INPUT TO BINARY STRING
L2: j BINC #BINARY CONVERTER
L3: add $s7, $s7, 7
j HOUT #HEX OUTPUT FROM BINARY STRING
L4: j PRINT #PRINT AND END

###################################
# READ AND STORE INPUT HEX #
###################################
INPUT: la $a0, PROMPT #LOAD THE ADDRESS OF PROMPT FOR HEX
li $v0, 4 #SYSTEM CALL FOR THE PRINT STRING
syscall #PRINT THE PROMPT
li $v0, 8 #SYSTEM CALL TO READ IN A STRING
move $a0,$s6
syscall #READ IN HEX
move $s0, $v0 #COPY ORIGIONAL HEX VALUE INTO s0
move $s0,$s6 #PUT TEMP HEX VALUE INTO s6
j START #CONVERT TO BINARY STRING

###################################
# HEX INPUT #
###################################

HIN: beq $s2,8,L2 #IF END OF HEX INPUT(8), BREAK
lb $s1,0($s0) #STORE CURRENT HEX CHAR IN $s1
sll $s3,$s3,4 #SHIFT LEFT 4 BITS FOR NEXT INPLACE
beq $s1,'0',IF0 #IF CHAR= 0
beq $s1,'1',IF1 #IF CHAR= 1
beq $s1,'2',IF2 #IF CHAR= 2
beq $s1,'3',IF3 #IF CHAR= 3
beq $s1,'4',IF4 #IF CHAR= 4
beq $s1,'5',IF5 #IF CHAR= 5
beq $s1,'6',IF6 #IF CHAR= 6
beq $s1,'7',IF7 #IF CHAR= 7
beq $s1,'8',IF8 #IF CHAR= 8
beq $s1,'9',IF9 #IF CHAR= 9
beq $s1,'a',IFA #IF CHAR= A
beq $s1,'b',IFB #IF CHAR= B
beq $s1,'c',IFC #IF CHAR= C
beq $s1,'d',IFD #IF CHAR= D
beq $s1,'e',IFE #IF CHAR= E
beq $s1,'f',IFF #IF CHAR= F
IF0: ori $s3,$s3,0
j RUTGER
IF1: ori $s3,$s3,1
j RUTGER
IF2: ori $s3,$s3,2
j RUTGER
IF3: ori $s3,$s3,3
j RUTGER
IF4: ori $s3,$s3,4
j RUTGER
IF5: ori $s3,$s3,5
j RUTGER
IF6: ori $s3,$s3,6
j RUTGER
IF7: ori $s3,$s3,7
j RUTGER
IF8: ori $s3,$s3,8
j RUTGER
IF9: ori $s3,$s3,9
j RUTGER
IFA: ori $s3,$s3,10
j RUTGER
IFB: ori $s3,$s3,11
j RUTGER
IFC: ori $s3,$s3,12
j RUTGER
IFD: ori $s3,$s3,13
j RUTGER
IFE: ori $s3,$s3,14
j RUTGER
IFF: ori $s3,$s3,15
j RUTGER

RUTGER:
addi $s2,$s2,1 #INCREASE I
addi $s0,$s0,1 #INCREASE POSITION
j HIN #RESTART LOOP
###################################
# BINARY CONVERTER #
###################################
BINC: li $s1,0 #CLEAR TEMP BYTE STORAGE
li $s2,0 #CLEAR I
srl $s4,$s3,1 #SHIFT RIGHT 1
xor $s3,$s3,$s4 #EXCLUSIVE OR TO CHANGE BINARY STRING
j L3 #NEXT STEP

###################################
# HEX OUTPUT #
###################################

HOUT: beq $s2,8,L4 #END OF BINARY STRING, BREAK
and $s5,$s3,0xf #GET CHAR
srl $s3,$s3,4 #'TYPEWRITTER' SHIFT RIGHT

beq $s5,0,IF0000 #IF BYTE= 0000
beq $s5,1,IF0001 #IF BYTE= 0001
beq $s5,2,IF0010 #IF BYTE= 0010
beq $s5,3,IF0011 #IF BYTE= 0011
beq $s5,4,IF0100 #IF BYTE= 0100
beq $s5,5,IF0101 #IF BYTE= 0101
beq $s5,6,IF0110 #IF BYTE= 0110
beq $s5,7,IF0111 #IF BYTE= 0111
beq $s5,8,IF1000 #IF BYTE= 1000
beq $s5,9,IF1001 #IF BYTE= 1001
beq $s5,10,IF1010 #IF BYTE= 1010
beq $s5,11,IF1011 #IF BYTE= 1011
beq $s5,12,IF1100 #IF BYTE= 1100
beq $s5,13,IF1101 #IF BYTE= 1101
beq $s5,14,IF1110 #IF BYTE= 1110
beq $s5,15,IF1111 #IF BYTE= 1111
IF0000: li $t0,'0'
sb $t0,0($s7)
j MUTGER
IF0001: li $t0,'1'
sb $t0,0($s7)
j MUTGER
IF0010: li $t0,'2'
sb $t0,0($s7)
j MUTGER
IF0011: li $t0,'3'
sb $t0,0($s7)
j MUTGER
IF0100: li $t0,'4'
sb $t0,0($s7)
j MUTGER
IF0101: li $t0,'5'
sb $t0,0($s7)
j MUTGER
IF0110: li $t0,'6'
sb $t0,0($s7)
j MUTGER
IF0111: li $t0,'7'
sb $t0,0($s7)
j MUTGER
IF1000: li $t0,'8'
sb $t0,0($s7)
j MUTGER
IF1001: li $t0,'9'
sb $t0,0($s7)
j MUTGER
IF1010: li $t0,'a'
sb $t0,0($s7)
j MUTGER
IF1011: li $t0,'b'
sb $t0,0($s7)
j MUTGER
IF1100: li $t0,'c'
sb $t0,0($s7)
j MUTGER
IF1101: li $t0,'d'
sb $t0,0($s7)
j MUTGER
IF1110: li $t0,'e'
sb $t0,0($s7)
j MUTGER
IF1111: li $t0,'f'
sb $t0,0($s7)
j MUTGER

MUTGER: sub $s7,$s7,1 #INCREASE POSITION
addi $s2,$s2,1 #INCREASE I
j HOUT #RESTART LOOP

###################################
# PRINT THE OUTPUT #
###################################
PRINT: sb $0,8($s6) #Seperate the inputs(/n -> 0)

la $s7, RES #RESET $s7
li $v0, 4 #LOADS SYSTEM CALL TO PRINT STRING
move $a0, $s6 #LOADS VALUE OF ORIGIONAL HEX TO CALL
syscall #PRINT MIN

la $a0, OUT #LOAD ADDRESS FOR FIRST STRING PART
li $v0, 4 #SYSTEM CALL TO PRINT STRING
syscall #PRINT STRING (" -> ")

li $v0, 4 #LOADS SYSTEM CALL TO PRINT STRING
move $a0, $s7 #LOADS VALUE OF FINALIZED HEX TO CALL
syscall #PRINT MIN

jr $ra #EXIT
#END PROGRAM



I'm sure it's not as optimimized as I would like, and I'm sure I could drop the number of registers down to around 4, but heck, it works and that'll all I care about.
*why Rutger and Mutger... I don't know. don't ask. I was running out of names for methods.

 

 

 


Reply

DeveloperX
Apr 11 2006, 06:59 AM
3 years ago I wrote HexToBin function.

CODE

function HexToBin(Hexadecimal: string): string;
const
  BCD: array [0..15] of string =
    ('0000', '0001', '0010', '0011', '0100', '0101', '0110', '0111',
    '1000', '1001', '1010', '1011', '1100', '1101', '1110', '1111');
var
  i: integer;
begin
  for i := Length(Hexadecimal) downto 1 do
    Result := BCD[StrToInt('$' + Hexadecimal[i])] + Result;
end;

procedure TForm1.Button1Click(Sender: TObject);
begin
  ShowMessage(HexToBin('FFA1'));
  // Returns 1111111110100001
end;


But for BinToHex(s:string) converting you can use standard BinToHex function in Math module.

And such code:
CODE

BinToHex = DecToHex(BinToDec(Bin)); //maybe works!


good luck!

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