Returning Back To The Beginning Of An If Statement

kvarnerexpress

Sep 10 2005, 04:05 PM

I have a bit of code. I am sooo close to figuring out. The only thing I need it to do, is return back to the beginning of the if statement after the new input is entered to determine of the new input meets the requirements. Here is my code:

Code:

CODE

int input() //request input from user
{
int size = 0, size_even = 0;

cout << " Please enter an odd number between 3 and 25: ";
cin >> size;

size_even = size % 2;

// if statement to determine if the number is between 3 and 25
if((size >= 3) && (size <= 25))
{
// nested if statement to determine if the number is even or odd
if(size_even == 0)
{
cout << " Invalid Entry! Please enter an ODD number between 3 and 25! ";
cin >> size;
}

else
cout << " This is an odd number. ";
}

else
cout << " Invalid Entry! Please enter a number BETWEEN 3 and 25!";
cin >> size;

return 0;
}

So for instance as it is now, if some one enters a number larger than 25, it prompts for a new number but that's it. I need it to prompt for the new number and then go back through the if statemtents to determine if it meets the conditions.

Thanks for anyhelp provided.

kvarnerexpress

Reply

sandbox

Sep 10 2005, 05:08 PM

Um, is this your homework?!

Look up control structures in your book.

You'll learn a lot more if you figure it out yourself. Once you read the section on control structures the answer will be clear.

If you are still stuck you should probably email your prof instead of this forum. Your prof will be a better resource in the long run.

good luck

Reply

Poe

Sep 16 2005, 08:18 AM

let me help him cheat

CODE

int input() //request input from user
{
int size = 0, size_even = 0;
bool bPass = false;
do
{
cout << " Please enter an odd number between 3 and 25: ";
cin >> size;
// if statement to determine if the number is between 3 and 25
if((size >= 3) && (size <= 25))
{
size_even = size % 2;
// nested if statement to determine if the number is even or odd
if(size_even == 0)
{
cout << " Invalid Entry! Please enter an ODD number between 3 to 25! ";
}
else
{
cout << " This is an odd number. ";
bPass = true;
}
}
else
cout << " Invalid Entry! Please enter a number BETWEEN 3 and 25!";
}while(!bPass)
return 0;
}

Reply

Spectre

Sep 17 2005, 05:59 PM

I would do something like:

CODE

...
do {
cout << " Please enter an odd number between 3 and 25: ";
cin >> size;
} while( size < 3 || size > 25 );
...

If this is your homework, I would suggest you do not ask for other people to solve it for you. You won't be able to post a message and wait for a reply on a forum during an exam.

Reply

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