Ok i can't believe I need help in php but I can't figure this out... If i have an array,
lets say called test, how do i get a certain value from that array when referencing it dynamically
by either a string or another variable? Example: CODE $test=array(1,2,5);
$name="test"; //Doesn't work: echo $$name[0]; /Doesn't
work: echo ${$name}[0]; ...

Hi all Im having problems with this peice of code: CODE   $result =
mysql_query("SELECT 'ID' FROM 'login' WHERE
username=$dusername",$link);      if($result != NULL){
    //username DOES exsist so they cant have it!
    include("scripts/userexsists.php"); The idea is, this query will take the
variable $dusername which is the usernbame that a user wants to have, and check it in the
database to see if it already exsists. and depending on whether it does or not it will inc...

Hello, I am trying to make an employee application. I was just wondering if anyone knows how to spot
a php code error, when the code directly around the line with the error looks the same. below is
some of my process.php code. I beleive the error is on line 41. QUOTE PHP parse error: PHP
Parse error: parse error, unexpected T_LNUMBER, expecting T_VARIABLE or '$' in
/home/wwwange/public_html/FORMS/forms/process.php on line 41 Process.php code: CODE
<?php include("global.inc.php"); $errors=0; $error="The foll...

Say I have a variable such as $nav_item and it had to contents Home . IE: CODE
$nav_item = 'Home'; How would I make so that $nav_item was an array and
had the following contents? CODE $nav_item = array ('h', 'o',
'm', 'e'); With the case changing (ie H would become h and U
would become u ) EDIT: Okay found out that I could change the case with
array_change_key_case ($nav_item, CASE_LOWER); ...

Can someone help me out with this one, please. I have a PHP script in which I am trying to write a
fairly complex piece of html and I can't seem to get the coding of the PHP echo statement.
There are single and double quotes scattered throughout this line of html and it is driving me nuts
attempting to manage the output. So far, the only way I can get it to work is to break the
echo'ing of the line of html code into the following lines of PHP: HTML echo "\t" ;
echo ' li > a href ="'; echo $full_dir . $file ; echo '" alt=" full-s...

I have a single page template which has a Form on it. Logic is to check for a valid Querystring and
place the variables accepted from a form back into the form and re-display this form with error or
acceptance messages. I'm sure everyone here has done this a million times. The Form accepts
data from a user for First name, Last name, email address, and message-body named
'note_wide' then re-displays the values into the Form, but for some reason, I can't get
the value to display into a Textarea. Sample of the php code is as follows: first the good one:...

I've got the following function, that has a function inside of it, when I run it I get the
followin error: PHP Code: CODE Fatal error: Call to a member function on a non-object in
See the code below where I get the error message. I'm guessing the scope of my varaibles is
messed up, but I'm not sure how to fix it. I've abbreviated the code so as to make it easier
to read. PHP Code: CODE function getMemberRegistrationForm( &$tpl, &$db ) {
   function displayRegistrationForm( $action, &$db, $defaults =...

I have a input box in a form called "button" and when the user clicks Submit! I want php to
determine whether or not this is a url or just text. All urls have "http://" in them so I have
decided I need a script which can determine whether or not "http://" is in a variable or a string.
The problem with using strings is that I've never needed to use them before (and thus have no
knowledge about them). When I was using asp, I knew there was a function called instr() but I
can't find php's equivalent. Does anybody know? Thanks in advance!...

Okay I'm very new to PHP still, although you may recognize me from the threa before, just go
finished finals so now back to PHP! On one page I accept an input which will tell the next page
how many form lines to generate, that part I have worked out, or so I think. Because the number of
forum fields could vary I need to have a number of forum variables, so I used this code: CODE
echo   "<td><input name=\"wname" . $appendval . "\"
type=\"text\" id=\"wname" . $appendval . "...

ok this is my config script that runs my site: CODE <? # Set up info for left column on the
top page: # It should begin with html tag <td> and finish with tag </td>
$top_leftcol=" <td width='195' bgcolor='#eeeeee'
 valign='top'> <table width='100%'  bgcolor='#777799' border=0
cellspacing='0' cellpadding='0'> <tr><td> <font
FACE='ARIAL, HELVETICA' color='#ffffff' size='-1'>  
<b>MMORPG Trade Center<...

I've created a form, nothing special, that uses a php script as a form action to input data into
mysql. Nothing special at all about this scenario. One thing I'd like to do is have the php
script redirect the user back to the html page that has the form the user just completed. I
don't want to have to hard code the url into the header function because I use this php script
with a bunch of other pages. Does PHP store the value of this page into some variable that the php
script can use? Thanks. kvarnerexpress...

I would be greatful if anyone could help me out, I have been stuck on this for a while. The problem
is that I have a drop down menu which I get the contents of from a database. Then when I press the
get details button I want to use the value selected in my drop down menu and pass it into an SQL
statement to recieve all te relevent info. Everything works if I specify a known variable, but the
problem seems to be passing a variable in which is part of the array. Below is the code for the drop
down menu and the Sql statement i'm trying to execute. drop down menu: �...

CODE elseif
("$username=''.$password=''.$fullname=''.$countr
y=''.$email=''") { print "<table border='0'
align='center' valign='center' width='400'
height='400'><tr><td align='center'><font
size='2'><b>You did not fill out all the fields</b><br><A
HREF='javascript:history.back()'><img
src='http://www.online.trap17.com/images/go_backb...