kvarnerexpress
Oct 26 2005, 12:03 PM
I've got the following function, that has a function inside of it, when I run it I get the followin error: PHP Code: CODE Fatal error: Call to a member function on a non-object in See the code below where I get the error message. I'm guessing the scope of my varaibles is messed up, but I'm not sure how to fix it. I've abbreviated the code so as to make it easier to read. PHP Code: CODE function getMemberRegistrationForm( &$tpl, &$db )
{
function displayRegistrationForm( $action, &$db, $defaults = NULL, $id = NULL )
{
global $registrationForm;
$registrationForm = new HTML_QuickForm('registrationForm');
$registrationForm->addElement('text', 'lname', 'Last Name:', array('size' => 40, 'maxlength' => 255 ));
}
if( $registrationForm->validate() ) // <-This is where I get an error
{
$registrationForm->freeze();
}
else
{
displayForm( $registrationForm, $tpl, 'additional_content');
}
}
getMemberRegistrationForm( $tpl, $db); Thanks,kvarnerexpress
Reply
dul
Oct 27 2005, 11:36 PM
*BLEEP*ing hell. What is your registrationForm's source. Does it include that Validate() functuon???
Reply
HmmZ
Oct 29 2005, 08:53 AM
First of all, sorry if i confuse you, i dont work with such codes (->,=>) Shouldn't the call to validate() need variables provided to send to ? Check if you defined all your functions correctly, check the following: *validate() *freeze() *displayForm() Hope this helps, even a little bit :/
Reply
magiccode9
Nov 3 2005, 09:13 AM
hi, kvarnerexpress i dont think that a function can within another function. but following the error displayed, it should be mean you have try to call an method but that method not included in a object ==> the HTML_QuickForm might not be a class. try search if it found HTML_QuickForm class or not. - hope this help
Reply
arboc7
Nov 4 2005, 01:14 AM
All I can think of is if validate() is a function that exists (and your other functions also exist) when the getMemberRegistrationForm() function executes... Sorry I can't help much...but good luck!!
Reply
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