Stenno
Oct 7 2007, 05:21 PM
Hey fellow coders, I'm having a problem. If you output a im indentifier in php with gd libary. With this method for example: CODE <?
header("(anti-spam-(anti-spam-(anti-spam-content-type:))) image/png");
$imgWidth = 50;
$imgHeight = 50;
$image=imagecreate($imgWidth, $imgHeight);
$colorBlack = imagecolorallocate($image, 0, 0, 0); // first color you define with colorallocate is also the color of the background of your image
imagepng ($image);
imagedestroy ($image);
// This gives you a page with a black image of 50x50 pixels.
?> If i look at the source code of that page, i see: QUOTE �JFIF�������;CREATOR: gd-jpeg v1.0 (using IJG JPEG v62), quality = 70
�C�
# %$" "!&+7/&)4)!"0A149;>>>%.DIC<H7=>;�C
;("(;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;��n�"�� ����������
����}�!1AQa"q2#BR$3br
%&'()*456789:CDEFGHIJSTUVWXYZcdefghijstuvwxyz
� �������
���w�!1AQaq"2B #3Rbr
$4%&'()*56789:CDEFGHIJSTUVWXYZcdefghijstuvwxyz
� ��?�(
( I get something similair to that. Now my question: How can i get back the image indentifier (the var $image in the sample code above), with only this weird code ?? Thanks very much in advance, Though i fear not many people here know how this can be done  [size="3"][/size]
Reply
truefusion
Oct 7 2007, 07:35 PM
Replace the first instance of the image variable with CODE $image = @imagecreate($imgWidth, $imgHeight); Then check the page out again.
Reply
Stenno
Oct 7 2007, 08:01 PM
Ohw sorry, thanks for warning. But that's not my question. It's just a quick sample script to explain my question better. Please read it carefully: i would like to know how i can recreate an image with only the weird data (in the quotes).
Reply
truefusion
Oct 8 2007, 12:02 AM
The weird data should be the image itself, it's like opening up an image in an ascii editor. Check out these functions: imagecreatefrompng, imagecreatefromjpeg, imagecreatefromgif, etc..
Reply
Stenno
Oct 8 2007, 05:20 AM
QUOTE imagecreatefromjpeg Create a new image from file or URL And i don't have a file, i only have a string with those weird chars. Or maybe there is some function to create a file first and then use imagecreatefromjpeg() ??
Reply
jlhaslip
Oct 8 2007, 05:31 AM
Sten, Maybe simply tell us exactly what you are trying to do here. You appear to be writing a script to dynamically create an image. And now you want to save it? Why? Just use the script when you need the image... If you really need to save a copy of the actual Image, run that script in your Browser and do a rt-click, save image as... to save it to your desktop. That's the beauty of the script, you don't need to save the image 
Reply
rvalkass
Oct 8 2007, 05:56 AM
QUOTE(Stenno @ Oct 7 2007, 06:21 PM)  Now my question: How can i get back the image indentifier (the var $image in the sample code above), with only this weird code ?? Put simply, I don't think you can. What you are asking to do is something similar to opening a binary file in a text editor, saving it, then trying to run it as a binary file - it just can't be done. For example, if you open the TuxKart binary in Kate, you get something like the following repeated for 8000 lines: CODE ELF ��4 d� 4 ( 4 4�4� 4 4�4� � �E� E� � p p\ �, � ȘȘ H H�H� P�td� ����<B <B Q�td /lib/ld-linux.so.2 GNU � _ ( � � ) > � � G ( � � � 5 � � � � � � : / 6 � i � 2 � e - � � � ] p u j : � � �
� � There is absolutely no way to turn that back into the binary to be able to use it again. This is pretty much what you are asking to do with your image. Perhaps if you explained why you need to convert the 'code' back into the variable, we might be able to give you a different method.
Reply
Stenno
Oct 9 2007, 02:33 PM
I already found the method to retrieve an image indentifier with only the weird code. It's like this: CODE <?
$data = 'iVBORw0KGgoAAAANSUhEUgAAABwAAAASCAMAAAB/2U7WAAAABl'
. 'BMVEUAAAD///+l2Z/dAAAASUlEQVR4XqWQUQoAIAxC2/0vXZDr'
. 'EX4IJTRkb7lobNUStXsB0jIXIAMSsQnWlsV+wULF4Avk9fLq2r'
. '8a5HSE35Q3eO2XP1A1wQkZSgETvDtKdQAAAABJRU5ErkJggg==';
//$data is the base64_encoded weird data
$data = base64_decode($data);
$im = imagecreatefromstring($data);
if ($im !== false) {
header('(anti-spam-content-type:) image/png');
imagepng($im);
}
else {
echo 'An error occurred.';
}
?> Thanks for your help though, and sorry for the weird explenation
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