Fatal Error - something about [] and strings

moldboy

Jul 10 2005, 05:20 AM

I have this variable that I want to take the value of to use as an array, now it is a slightly odd variable it's one that I get by combinin a word and a number and then calling the information stored in that var, so ${${word . $number}}, anywho I get the following error
Fatal error: [] operator not supported for strings in and then the path

palladin

Jul 10 2005, 04:47 PM

Can you put little more code

from this i see only FatalError

and no idea what you try to do

but ...

Array ID can got only numbers
NameImage[1] = "one";
NameImage[2] = "two";
...
so ...

$id = 'bolek';
$number = 1.$id;
NameImage[$number] give you error

$id = 5;
$number = 1*$id; //give(5) or $number = 1.$id; //give(15)
NameImage[$number]; give you value from array

if this not give you answer put more code and write cleary what you wanna do

--------------------

Practice is when evrything is work but no one know why.
Theory is when work nothing but evry one know why.
Programmers join Practice with Theory - nothing work and no one know why

moldboy

Jul 10 2005, 05:05 PM

I've actualy changed my array structuring system to use the array() function But I post what I wanted to do anyway,
Let's pretend that I have 3 pages, on the first page the user enters a number, we'll say 4
on the next page using a while loop and code simmilar to the following the page generates a form field with 4 text boxes:

CODE

//form junk up here, don't feel like typing
$break = 0
$number = 1
while ($userinput > $break){
echo "<tr>";
echo "<input type=\"text\" name=\"inputarr" . $number . "\">";
echo "</tr>";
break++;
number++;
}
//bunch more code here

THis would build frou text inputs with the variables inputarr1 inputarr2 inputarr3 inputarr4.

Now I wanted to store information in an array form in the values that the user entered, so if inputarr1 was cookie, I want to create a array called $cookie with information, so:

CODE

${${inputarr . $number}}[] = whatever information;

bearing in mind that the $number would be deffined simmilar to the above example. This returned an error, the funny thing is I built this and it worked relativly well it didn't return the final output I wanted but no errors, so I went to watch TV and make a more complex example and when I cam back I recieved an error so I tried my simple example again and I go the same error, but now I've switched to using the array() function it workes like it did, not the correct answer but an answer.

sachavdk

Jul 15 2005, 01:09 AM

Isn't it easier to do it in a way like this:

CODE

<?
$var1 = "foo";
$var2 = "bar";

$foobar = "the_thing_you_want";

eval("\$finalvar = \$".$var1.$var2.";");

echo $finalvar;
?>

The code above will write the_thing_you_want on the screen

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