Jul 24, 2008

C Code, Can U Solve This? - Another interesting problem
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C Code, Can U Solve This? - Another interesting problem

8bit
Feb 1 2005, 02:08 AM
CODE

void fun(void)
{
 return 0;
}


XD Who wants it to print 20 lets just end the program now!

Reply

osknockout
Feb 1 2005, 02:11 AM
8bit, you can't do that (can have only 1 return 0;)
Cse-icons you devil, who the hell would
do that? Just playing around of course, I
didn't get it. I'm too practical laugh.gif

Reply

8bit
Feb 4 2005, 01:37 AM
CODE

void fun(void)
{
 int * ptr =&i;
 *ptr=50;
}


Beat that.

Reply

ankitunlimited
Mar 31 2006, 07:33 AM
QUOTE(8bit @ Feb 4 2005, 07:07 AM) *

CODE

void fun(void)
{
 int * ptr =&i;
 *ptr=50;
}


Beat that.


i dont know c, but c++. In c++, you cant access i anywhere else but main()

Reply

fotomaniak
Apr 23 2006, 03:21 AM
void fun()
{
int i=0;
while(true) i++;
}
overflow and program will end... or user will kill the program after waiting for a bit.

--------------------------------
void fun()
{
int *i=0;
while(true) *(i++)=i;
}
same as above plus there is a chance that program corrupts some critical data and crashes



Reply

WindAndWater
Apr 23 2006, 06:09 PM
QUOTE(cse-icons @ Nov 17 2004, 03:07 AM) *
How do I manipulate and change the value of i?


Technically you aren't changing the value of i -- you're defining a new i (it's at a new memory address). To answer your puzzle, you can change the value of i using an ASM injection attack using a noop sled to compensate for the variance in memory allocation addresses.

Reply

iGuest
Dec 13 2007, 03:53 AM
Need help... Need a program on turbo see (the theme is christmas)... Newbie at turbo see...

Reply

omarsdali
Dec 13 2007, 06:39 AM
QUOTE
8bit, you can't do that (can have only 1 return 0;)


The reason why he can't do it is because the return type is void, but if it was int like this:

int fun(void)
{

}

then he can do it.

Reply

Csshih
Dec 13 2007, 06:12 PM
Oh yea?
void fun(void)
{
randomlineofetext(3249830325)
}
the program won't print anything at all xD

Reply

klusk
Feb 25 2008, 02:26 PM
QUOTE(8bit @ Feb 4 2005, 07:07 AM) *
CODE
void fun(void)
{
  int * ptr =&i;
  *ptr=50;
}


Beat that.

This code wont work as the variable i is undeclared for fun()....it would have worked if "i" had been a global variable

There is another way if you wish to use pointers...


CODE
void fun(int *ptr)
{
  *ptr=50;
}


int main()
{
int i = 20;
fun(&i);
printf("i = %d\n", i);
return 0;
}



the output will be 50

Reply


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