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Feb 10 2005, 03:26 AM
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#1
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Member [Level 2] ![]() ![]() ![]() ![]() ![]() Group: Members Posts: 81 Joined: 3-August 04 Member No.: 609 |
This isn't a very long tutorial. I get asked this often, so here is the solution. The following code will return a string containing a number that has commas appropriately placed:
Code: myStringOrProperty = FormatNumber(3587532789053, 0) The second parameter (0) represents how many decimal places you want the returned number to go out to. Unless your number contains its own decimal, you probably don't want .00 at the end of every number you have. The above code would return: 3,587,532,789,053 This should make life easier for many... |
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