 Need Help On C++, It's my first assignment |
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 Jan 19 2006, 07:01 AM
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#1
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Advanced Member  Group: Members Posts: 132 Joined: 22-November 05 Member No.: 14,730  |
well guys, I'm very new to C++, and I've just received my new assignment today but don't know what does it mean, so I was hoping that you could help me out with it.
In my assignment, I'm required to write a program that does the following. - It first lists each of the basic data types, stating the number of bits they use, their min and max values, and for floating point types, their min and max exponent values. - Then have the program prompt the user to enter a number and reply stating what number the user entered. - Must be presented all output to the user in a nice, userfriendly manner. My lecturer said something about do not hard code it out at the end of the class. |
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Jan 25 2006, 04:23 AM
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#2
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Premium Member Group: Members Posts: 178 Joined: 13-October 04 From: NSW, Australia Member No.: 1,713 |
you can use the 'sizeof' command to determine the size of a variable. I'm not sure if it's in bits or bytes (probably bytes) but there are 8 bits for every byte. As for input and output, there's heaps of basic tutorials around that'll get you what you need. Here's a good place to start: http://www.cprogramming.com/tutorial/lesson1.html.
Good Luck! 
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Jan 25 2006, 08:26 AM
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#3
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Premium Member Group: Members Posts: 165 Joined: 12-September 05 Member No.: 11,777 |
#include <float.h>
#include <limit.h> this two header contains the values; char CHAR_MIN, CHAR_MAX int minimum = INT_MIN, maximum = INT_MAX long LONG_MIN or LNG_MIN i forgot... LONG_MAX or LNG_MAX float FLT_MIN, FLT_MAX double DBL_MIN, DBL_MAX heres how to use this constants in c++ style CODE #include <limit.h> #include <iostream> void main() { cout << "INTEGER MINIMUM = " << INT_MIN << " INTEGER MAXIMUM = " << INT_MAX; } this simple code will display the minimum and maximum value an integer can hold and don't be startled if long and int will have the same value  since most implementation uses 4 bytes for long and 4 bytes for int. If you want the 2 bytes integer.. use the shortto prompt user use this code CODE int number; cout << "enter number: "; cin >> number; count << endl << "the number u entered is " << number; i hope this helps.. if not
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Jan 25 2006, 06:08 PM
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#4
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Advanced Member Group: Members Posts: 132 Joined: 22-November 05 Member No.: 14,730 |
i cam up with something like this:
CODE #include <iostream> #include <climits> using namespace std; int main() { int n_int = INT_MAX; short n_short = SHRT_MAX; long n_long = LONG_MAX; cout << "int is " << sizeof (int) << "bytes. " << endl; cout << "short is " << sizeof n_short << "bytes. " << endl; cout << "long is " << sizeof n_long << "bytes. " << endl; cout << "Maximum values:" << endl; cout << "int: " << n_int << endl; cout << "short: " << n_short << endl; cout << "long: " << n_long << endl; cout << "Minimum int value = " << INT_MIN << endl; cout << "Bits per byte = " << CHAR_BIT << endl << endl; int number; cout << "Enter number: "; cin >> number; cout << endl << "The number u entered is " << number; cin.get(); cin.get(); return 0; } But I'm not sure if it complies with what my lecturer wants, so can someone please check it out for me?
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Jan 29 2006, 07:35 AM
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#5
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Advanced Member Group: Members Posts: 132 Joined: 22-November 05 Member No.: 14,730 |
OK, this is what I got now, and i'm pretty sure that this is what the assignment is suppose to be like. Hope that someone will look it over for me and tell me if i'm doingmething wrong here
This is just the code for listing the data types. CODE #include <iostream> #include <climits> #include <cfloat> using namespace std; int main() { cout << "bool\t" << sizeof(bool)*8 << "\t" << 0 << "\t" << 1 << endl; cout << "char\t" << sizeof(char)*8 << "\t" << CHAR_MIN << "\t" << CHAR_MAX << endl; cout << "short\t" << sizeof(short)*8 << "\t" << SHRT_MIN << "\t" << SHRT_MAX << endl; cout << "int\t" << sizeof(int)*8 << "\t" << INT_MIN << "\t" << INT_MAX << endl; cout << "long\t" << sizeof(long)*8 << "\t" << LONG_MIN << "\t" << LONG_MAX << endl; cout << "float\t" << sizeof(float)*8 << "\t" << FLT_MIN << "\t" << FLT_MAX << endl; cout << "double\t" << sizeof(double)*8 << "\t" << DBL_MIN << "\t" << DBL_MAX << endl; cout << "double long\t" << sizeof(double long)*8 << "\t" << LDBL_MIN << "\t" << LDBL_MAX << endl; cin.get(); cin.get(); return 0; } |
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